题目内容
(105
+20
)÷7
÷(51
+25
)×4
=( )
| 4 |
| 19 |
| 19 |
| 99 |
| 2 |
| 11 |
| 10 |
| 39 |
| 24 |
| 79 |
| 5 |
| 13 |
| A、1 | ||
B、51
| ||
C、
| ||
D、
|
分析:按运算顺序,先算乘除,后算加减,有括号的先算括号里面的.
解答:解:原式=(105
+20
)×
÷(51
+25
)×
=125
×
÷76
×
=
×
×
×
=
=
=
≈1,
故选A.
| 396 |
| 1881 |
| 361 |
| 1881 |
| 11 |
| 79 |
| 790 |
| 3081 |
| 936 |
| 3081 |
| 57 |
| 13 |
=125
| 757 |
| 1881 |
| 11 |
| 79 |
| 1762 |
| 3081 |
| 57 |
| 13 |
=
| 235882 |
| 1881 |
| 11 |
| 79 |
| 3081 |
| 235918 |
| 57 |
| 13 |
=
| 235882×1027 |
| 79×235918×13 |
=
| 235882 |
| 235918 |
=
| 117941 |
| 117959 |
≈1,
故选A.
点评:本题考查了有理数的混合运算,题目的式子较长,是一道竞赛题,难度较大.
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