题目内容
计算
(1)|-2|-
+(π-3)°
(2)(1+
)÷
(1)|-2|-
| 9 |
(2)(1+
| x-2 |
| x+2 |
| 2x |
| x2-4 |
(1)原式=2-3+1=0;
(2)原式=
×
=x-2.
(2)原式=
| 2x |
| x+2 |
| (x+2)(x-2) |
| 2x |
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题目内容
| 9 |
| x-2 |
| x+2 |
| 2x |
| x2-4 |
| 2x |
| x+2 |
| (x+2)(x-2) |
| 2x |