题目内容
计算:
(1)1+(-2)+|-2-3|-5
(2)[50-(
-
+
)×(-6)2]÷(-72)
(1)1+(-2)+|-2-3|-5
(2)[50-(
| 7 |
| 9 |
| 11 |
| 12 |
| 1 |
| 6 |
分析:(1)先去括号及绝对值符号,再从左到右依次计算即可;
(2)先算小括号,再算中括号,最后算除法即可.
(2)先算小括号,再算中括号,最后算除法即可.
解答:解:(1)原式=1-2+5-5
=-1+5-5
=-1;
(2)原式=[50-(
-
+
)×36]÷(-49)
=[50-
×36+
×36-
×36]÷(-49)
=[50-28+33-6]÷(-49)
=49÷(-49)
=-1.
=-1+5-5
=-1;
(2)原式=[50-(
| 7 |
| 9 |
| 11 |
| 12 |
| 1 |
| 6 |
=[50-
| 7 |
| 9 |
| 11 |
| 12 |
| 1 |
| 6 |
=[50-28+33-6]÷(-49)
=49÷(-49)
=-1.
点评:本题考查的是有理数的混合运算,熟知有理数混合运算的顺序是解答此题的关键.
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