题目内容

计算题:
(1)30+(-4)2÷(-
1
2
)-2

(2)(3a23-(a42-(-5a52-(a22
(3)(x+2)(x-2)(x2+4)
(4)(a+3)2(a-3)2
(1)原式=1+16÷4
=1+4
=5;

(2)原式=27a6•a8-25a10•a4
=27a14-25a14
=2a14

(3)原式=(x2-4)(x2+4)
=x4-16;

(4)原式=[(a+3)(a-3)]2
=(a2-9)2
=a4-18a2+81.
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