题目内容

如图,在正方形中,为对角线上一点,联结,延长于点

(1)求证:

(2)当时,求证:

答案:(1)∵四边形是正方形,∴,且   (2分)

又∵是公共边,∴△≌△,                              (2分)

∴∠ =∠                                                 (1分)

(2)联结                                                             (1分)

∴∠ =∠                                                 (1分)

∵∠=∠,∠ =∠

∴∠=∠

∵∠+∠=∠+∠

∴∠=∠                                                   (1分)

∵四边形是正方形,

∴∠= =45°,∠== 45°,

∴∠=∠                                                  (1分)

∴∠=∠.                                                 (1分)

又∵∠是公共角,∴△∽△,                           (1分)

,即                                        (1分)

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