题目内容
式4a+3ab-| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 3 |
分析:根据题意列出式子,去括号后合并同类项即可.
解答:解:(4a+3ab-
b)-(-2a-
ab+
b)
=4a+3ab-
b+2a+
ab-
b
=6a+
ab-
b.
故答案为:6a+
ab-
b.
| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 3 |
=4a+3ab-
| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 3 |
=6a+
| 9 |
| 2 |
| 5 |
| 6 |
故答案为:6a+
| 9 |
| 2 |
| 5 |
| 6 |
点评:本题主要考查对整式的加减,合并同类项,去括号法则等知识点的理解和掌握,能根据题意列出代数式是解此题的关键.
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