题目内容
计算:
(1)(-2)3+3×(-1)2012-|-4|×5;
(2)-1
+1+1
×[-(-
)÷(-
)-2
];
(3)[-24÷(-2
)2+5
×(-
)-
]÷
.
(1)(-2)3+3×(-1)2012-|-4|×5;
(2)-1
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 2 |
| 3 |
(3)[-24÷(-2
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 4 |
| 1 |
| 12 |
分析:(1)根据有理数的混合运算顺序和法则分别进行计算,先算乘方和绝对值,再算乘法,然后合并即可;
(2)先算小括号,再算中括号,最后把所得的结果合并即可;
(3)先算算小括号里面的,然后再用乘法的分配律进行计算即可.
(2)先算小括号,再算中括号,最后把所得的结果合并即可;
(3)先算算小括号里面的,然后再用乘法的分配律进行计算即可.
解答:解:(1)(-2)3+3×(-1)2012-|-4|×5
=-8+3×1-4×5
=-8+3-20
=-25;
(2)-1
+1+1
×[-(-
)÷(-
)-2
]
=-1
+1+
×[
×(-4)-
]
=-1
+1+
×[-
-
]
=-1
+1+
×(-4)
=-1
+1-6
=-6
;
(3)[-24÷(-2
)2+5
×(-
)-
]÷
=[-16÷
-
-
]×12
=[-16×
-
-
]×12
=-27-11-3
=-41.
=-8+3×1-4×5
=-8+3-20
=-25;
(2)-1
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 2 |
| 3 |
=-1
| 1 |
| 2 |
| 3 |
| 2 |
| 1 |
| 3 |
| 8 |
| 3 |
=-1
| 1 |
| 2 |
| 3 |
| 2 |
| 4 |
| 3 |
| 8 |
| 3 |
=-1
| 1 |
| 2 |
| 3 |
| 2 |
=-1
| 1 |
| 2 |
=-6
| 1 |
| 2 |
(3)[-24÷(-2
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 4 |
| 1 |
| 12 |
=[-16÷
| 64 |
| 9 |
| 11 |
| 12 |
| 1 |
| 4 |
=[-16×
| 9 |
| 64 |
| 11 |
| 12 |
| 1 |
| 4 |
=-27-11-3
=-41.
点评:此题考查了有理数的混合运算,掌握运算顺序和法则是解题的关键,能用简便方法的要用简便方法,注意结果的符号.
练习册系列答案
相关题目