题目内容
计算:
(1)8(x-1)2=98
(2)-32÷
×
-
+
×(-
).
(1)8(x-1)2=98
(2)-32÷
|
| 2 |
| 3 |
| 3 |
| ||
| (-3)2×2 |
| ||
| 3 |
(1)系数化为1得:(x-1)2=
,
开平方得:x-1=±
,
解得:x1=
,x2=-
.
(2)原式=-9÷
×
-
+3
×(-
)
=-6×
-
-2
=-4-
-2
=-6
.
| 49 |
| 4 |
开平方得:x-1=±
| 7 |
| 2 |
解得:x1=
| 9 |
| 2 |
| 5 |
| 2 |
(2)原式=-9÷
| 3 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| ||
| 3 |
=-6×
| 2 |
| 3 |
| 1 |
| 2 |
=-4-
| 1 |
| 2 |
=-6
| 1 |
| 2 |
练习册系列答案
相关题目