题目内容
化简
-
=
．
| 2x |
| x2-64y2 |
| 1 |
| x-8y |
| 1 |
| x+8y |
| 1 |
| x+8y |
分析：首先通分，然后利用同分母的分式相加减的运算法则求解即可，注意运算结果需化为最简．
解答：解：
-
=
-
=
=
=
．
故答案为：
．
| 2x |
| x2-64y2 |
| 1 |
| x-8y |
=
| 2x |
| (x+8y)(x-8y) |
| x+8y |
| (x+8y)(x-8y) |
=
| 2x-x-8y |
| (x+8y)(x-8y) |
| x-8y |
| (x+8y)(x-8y) |
=
| 1 |
| x+8y |
故答案为：
| 1 |
| x+8y |
点评：此题考查了分式的加减运算法则．此题比较简单，注意掌握通分的知识，注意运算结果需化为最简．
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