题目内容
先化简,再选择使原式有意义而你喜欢的数代入求值:| 1 |
| x+1 |
| x+2 |
| x2-1 |
| x2-2x+1 |
| x 2+4x+4 |
分析:将分式的分子、分母因式分解,约分、通分,再代值计算,注意x≠±1,-2.
解答:解:原式=
-
•
=
-
=
=
=
,
当x=0时,原式=
.
| 1 |
| x+1 |
| x+2 |
| (x+1)(x-1) |
| (x-1)2 |
| (x+2)2 |
| 1 |
| x+1 |
| x-1 |
| (x+1)(x+2) |
=
| x+2-x+1 |
| (x+1)(x+2) |
| 3 |
| (x+1)(x+2) |
| 3 |
| x2+3x+2 |
当x=0时,原式=
| 3 |
| 2 |
点评:本题考查了分式的化简运算.关键是根据分式化简的顺序,因式分解,约分、通分,再代值计算.
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