题目内容
已知x=
,y=
,则x3+12xy+y3=________
64
分析:由已知得xy=1,x+y=4,运用公式x3+y3=(x+y)(x2-xy+y2)=(x+y)[(x+y)2-3xy],整体代入即可.
解答:∵x=
=2-
,y=
=2+
,
∴xy=1,x+y=4,
∴x3+12xy+y3=12+x3+y3,
=12+(x+y)(x2-xy+y2),
=12+(x+y)[(x+y)2-3xy],
=12+4×(42-3×1),
=64.
故本题答案为64.
点评:本题考查了二次根式的化简与求值,将已知条件变形,再整体代入是解题的关键,不化简,直接代入,运算很复杂.
分析:由已知得xy=1,x+y=4,运用公式x3+y3=(x+y)(x2-xy+y2)=(x+y)[(x+y)2-3xy],整体代入即可.
解答:∵x=
∴xy=1,x+y=4,
∴x3+12xy+y3=12+x3+y3,
=12+(x+y)(x2-xy+y2),
=12+(x+y)[(x+y)2-3xy],
=12+4×(42-3×1),
=64.
故本题答案为64.
点评:本题考查了二次根式的化简与求值,将已知条件变形,再整体代入是解题的关键,不化简,直接代入,运算很复杂.
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