题目内容
化简式子
÷(y+2-
)的结果是
.
| y-3 |
| 4y-8 |
| 5 |
| y-2 |
| 1 |
| 4(y+3) |
| 1 |
| 4(y+3) |
分析:先算括号里面的,再根据分式的除法法则进行计算.
解答:解:原式=
÷
=
×
=
.
故答案为:
.
| y-3 |
| 4(y-2) |
| (y+3)(y-3) |
| y-2 |
=
| y-3 |
| 4(y-2) |
| y-2 |
| (y+3)(y-3) |
=
| 1 |
| 4(y+3) |
故答案为:
| 1 |
| 4(y+3) |
点评:本题考查的是分式的混合运算,熟知分式混合运算的法则是解答此题的关键.
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