题目内容
先化简，再求值：（
-
）÷
，x=-2．
| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x3-2x2 |
原式=（
-
）÷
=
×
=
×
=
×
=
，
当x=-2时，原式=
=
．
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x-4 |
| x2(x-2) |
=
| (x+2)(x-2)-x(x-1) |
| x(x-2)2 |
| x2(x-2) |
| x-4 |
=
| x2-4-x2+x |
| x(x-2)2 |
| x2(x-2) |
| x-4 |
=
| x-4 |
| x(x-2)2 |
| x2(x-2) |
| x-4 |
=
| x |
| x-2 |
当x=-2时，原式=
| -2 |
| -2-1 |
| 2 |
| 3 |
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