Question

已知：如图，AB⊥BE于点B，DE⊥BE于点E，F、C在BE上，AC、DF相交于点G，且AB＝DE，BF＝CE．
求证： GF＝GC．

Answer 1

证明: ∵AB⊥BE，DE⊥BE
∴ÐABC=ÐDEF=90°                         
∵BF＝CE
∴BC="EF                                   "
又∵AB＝DE                                
∴△ABC≌△DEF                              
∴ÐACB=ÐDFE                                
∴GF＝GC   解析:
略