题目内容
计算:
(1)(-2a3b2)2÷a3b2•b2
(2)(
)2-
+4×
.
(1)(-2a3b2)2÷a3b2•b2
(2)(
| 2 |
| (-4)2 |
| 3 |
| ||
(1)原式=4a6b4÷a3b2•b2
=4a6-3b4-2+2
=4a3b4;
(2)原式=2-4+4×
=2-4+2
=0.
=4a6-3b4-2+2
=4a3b4;
(2)原式=2-4+4×
| 1 |
| 2 |
=2-4+2
=0.
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