题目内容
计算:
(1)-2×(-
)-|-23|-5÷6-(-
)
(2)(
-
-
)÷(-
)+(-
)
(1)-2×(-
| 3 |
| 5 |
| 1 |
| 3 |
(2)(
| 7 |
| 4 |
| 7 |
| 8 |
| 7 |
| 12 |
| 7 |
| 8 |
| 8 |
| 3 |
分析:(1)先算乘方、乘法、除法,再合并即可.
(2)先算除法,再求出即可.
(2)先算除法,再求出即可.
解答:解:(1)原式=
-8-
+
=-7
.
(2)原式=
×(-
)-
×(-
)-
×(-
)-
=-2+1+
-
=-1-2
=-3.
| 6 |
| 5 |
| 5 |
| 6 |
| 1 |
| 3 |
=-7
| 3 |
| 10 |
(2)原式=
| 7 |
| 4 |
| 8 |
| 7 |
| 7 |
| 8 |
| 8 |
| 7 |
| 7 |
| 12 |
| 8 |
| 7 |
| 8 |
| 3 |
=-2+1+
| 2 |
| 3 |
| 8 |
| 3 |
=-1-2
=-3.
点评:本题考查了有理数的混合运算的应用,主要考查学生的计算能力.
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