题目内容
化简:(1)| m-m2 |
| m2-1 |
| m |
| m-1 |
| m+1 |
| m-1 |
(2)1-
| x-y |
| x+2y |
| x2-y2 |
| x2+4xy+4y2 |
分析:(1)乘除属于同级运算,必须从左到右计算;
(2)运算顺序是:先算乘除,再算加减.
(2)运算顺序是:先算乘除,再算加减.
解答:解:(1)原式=
•
•
=
;
(2)原式=1-
•
=1-
=
=-
.
故答案为
、-
.
| -m(m-1) |
| (m+1)(m-1) |
| m-1 |
| m |
| (m+1)2 |
| (m-1)2 |
=
| 1+m |
| 1-m |
(2)原式=1-
| x-y |
| x+2y |
| (x+2y)2 |
| (x+y)(x-y) |
=1-
| x+2y |
| x+y |
| x+y-x-2y |
| x+y |
=-
| y |
| x+y |
故答案为
| 1+m |
| 1-m |
| y |
| x+y |
点评:考查分式的化简,分式的化简关键在于通过通分、合并同类项、因式分解、约分转化为最简分式.
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