题目内容
计算:
-
•
.
| 1 |
| x+1 |
| x+2 |
| x2-1 |
| x2-2x+1 |
| x2+4x+4 |
分析:根据分式混合运算的法则进行计算即可.
解答:解:原式=
-
•
=
-
=
=
.
| 1 |
| x+1 |
| x+2 |
| (x+1)(x-1) |
| (x-1)2 |
| (x+2)2 |
=
| 1 |
| x+1 |
| x-1 |
| (x+1)(x+2) |
=
| x+2-x+1 |
| (x+1)(x+2) |
=
| 3 |
| (x+1)(x+2) |
点评:本题考查的是分式的混合运算,在解答此类题目时要注意通分及约分的灵活应用.
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