题目内容
已知:如图,以Rt△ABC的三边为斜边分别向外作等腰直角三角形.若斜边AB=6,则图中阴影部分的面积为______.
设两条直角边是a,b,则a2+b2=62,
则S阴影=
(
a)2+
(
b)2+
(3
)2
=
×
(a2+b2)+
×18
=
×36+
×18
=18.
则S阴影=
| 1 |
| 2 |
| ||
| 2 |
| 1 |
| 2 |
| ||
| 2 |
| 1 |
| 2 |
| 2 |
=
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
=
| 1 |
| 4 |
| 1 |
| 2 |
=18.
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