题目内容
先化简,再求值:| 2 |
| x2-1 |
| 1 |
| x-1 |
| 2 |
| x+1 |
| 2 |
分析:先把分式通分、化简,再把数代入求值.
解答:解:原式=
=
=
,
当x=
-1时,
原式=
=
.
| 2-(x+1)+2(x-1) |
| (x+1)(x-1) |
=
| x-1 |
| (x+1)(x-1) |
=
| 1 |
| x+1 |
当x=
| 2 |
原式=
| 1 | ||
|
| ||
| 2 |
点评:此题是分式的减法,要先将分母分解因式,找到最简公分母再通分.
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