题目内容
(-2a2b)3=______;-3ab3•(-4a2b)=______;(
)-1+(3-π)0=______.
| 1 |
| 3 |
(-2a2b)3=(-2)3a2×3 b3=-8a6b3;
-3ab3•(-4a2b)=(-3)×(-4)a1+2b3+1=12a3b4;
(
)-1+(3-π)0=3+1=4.
故答案为:-8a6b3;12a3b4;4.
-3ab3•(-4a2b)=(-3)×(-4)a1+2b3+1=12a3b4;
(
| 1 |
| 3 |
故答案为:-8a6b3;12a3b4;4.
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