题目内容
计算:
①(
•
)÷
;
②(
+x-y)(
-x-y).
①(
| a-2 |
| a2 |
| a-1 |
| a2-4a+4 |
| a-1 |
| a |
②(
| 4xy |
| x-y |
| 4xy |
| x+y |
分析:(1)先计算括号里的,再计算括号外的即可;
(2)先通分计算括号里的,再相乘即可.
(2)先通分计算括号里的,再相乘即可.
解答:解:(1)原式=
×
×
=
;
(2)原式=
×
=
×
=-(x+y)(x-y)=-x2+y2.
| a-2 |
| a2 |
| a-1 |
| (a-2)2 |
| a |
| a-1 |
| 1 |
| a(a-2) |
(2)原式=
| 4xy+(x-y)2 |
| x-y |
| 4xy-(x+y)2 |
| x+y |
| (x+y)2 |
| x-y |
| -(x-y)2 |
| x+y |
点评:本题考查了分式的混合运算,解题的关键是通分、约分,并注意分子分母的因式分解.
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