题目内容
(2012•镇江)(1)计算:
-4sin45°+(-2012)0;
(2)化简:
÷(x+1).
| 2 |
(2)化简:
| x-1 |
| x2-2x+1 |
分析:(1)根据特殊角的三角函数值、零指数幂求出sin45°和(-2012)0的值,再代入求出即可;
(2)先分解因式,同时把除法变成乘法,再约分,即可求出答案.
(2)先分解因式,同时把除法变成乘法,再约分,即可求出答案.
解答:(1)解:原式=
-4×
+1
=
-2
+1
=1-
;
(2)解:原式=
×
=
=
.
| 2 |
| ||
| 2 |
=
| 2 |
| 2 |
=1-
| 2 |
(2)解:原式=
| x-1 |
| (x-1)2 |
| 1 |
| x+1 |
=
| 1 |
| (x-1)(x+1) |
=
| 1 |
| x2-1 |
点评:本题考查了特殊角的三角函数值、零指数幂、分式的混合运算等知识点,关键是考查学生能否熟练地运用知识点进行计算和化简,题目比较好,难度适中.
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