题目内容
当x=| 2 |
| x |
| x+1 |
| x+3 |
| x+1 |
| x2-1 |
| x2+4x+3 |
分析:把分式化简,然后把x的值代入化简后的式子求值就可以了.
解答:解:原式=
-
•
=
-
=
,
当x=
-1时,
原式=
=
.
| x |
| x+1 |
| x+3 |
| x+1 |
| (x+1)(x-1) |
| (x+1)(x+3) |
=
| x |
| x+1 |
| x-1 |
| x+1 |
| 1 |
| x+1 |
当x=
| 2 |
原式=
| 1 | ||
|
| ||
| 2 |
点评:分式先化简再求值的问题,难度不大.
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