题目内容
(1)计算:([(-| 3 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 3 |
(2)计算:(-1)2001+(-5)2×|1-
| 2 |
| 5 |
(3)计算:|-
| 1 |
| 2 |
| 1 |
| 22 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 9 |
(4)计算:{1+[
| 1 |
| 16 |
| 3 |
| 4 |
| 2 |
| 3 |
分析:(1)首先计算小括号,然后计算中括号,最后计算除法即可求解;
(2)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
(3)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
(4)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
(2)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
(3)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
(4)首先计算乘方,然后计算乘除法、最后计算加减即可求解;
解答:解:①[(-
)-
+(-1)3]÷[2
-3
+(-1)6]
=(-
)÷(-
)=
;
(2)(-1)2001+(-5)2×|1-
|+22÷(-1)3
=-1+25×
-4
=10;
(3)|-
|2+
+(-1)101-1
×(0.5-
)÷1
=
+
-1+
×
×
=-
;
(4){1+[
-(-
)3]×(-2)4}÷(-1
)2
=(1+
×16)×
=
.
| 3 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 3 |
=(-
| 17 |
| 8 |
| 1 |
| 12 |
| 51 |
| 2 |
(2)(-1)2001+(-5)2×|1-
| 2 |
| 5 |
=-1+25×
| 3 |
| 5 |
=10;
(3)|-
| 1 |
| 2 |
| 1 |
| 22 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 9 |
=
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 2 |
| 1 |
| 6 |
| 9 |
| 10 |
=-
| 11 |
| 40 |
(4){1+[
| 1 |
| 16 |
| 3 |
| 4 |
| 2 |
| 3 |
=(1+
| 31 |
| 64 |
| 9 |
| 25 |
=
| 63 |
| 20 |
点评:此题主要考查了有理数的混合运算,其中计算时首先计算括号内面,然后计算乘除,最后计算加减即可求解.
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