题目内容
先化简,再求值:
÷
-(x-2)-1+1(其中x=
)
| 2x-2 |
| x2-x-2 |
| x2-2x+1 |
| x2-1 |
| 4 | ||
|
分析:先对x进行整理,再对要求的式子进行化简,然后把x的值代入即可求出答案;
解答:解:∵x=
=
+1,
∴原式=
•
-
+1=
,
=
,
=
;
| 4 | ||
|
| 5 |
∴原式=
| 2(x-1) |
| (x-2)(x+1) |
| (x-1(x+1)) |
| (x-1)2 |
| 1 |
| x-2 |
| x-1 |
| x-2 |
=
(
| ||
(
|
=
5+
| ||
| 4 |
点评:此题考查了整式的化简求值;先把要求的式子进分母有理化是解题的关键,解题时要细心.
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