题目内容
计算
(1)
+(-2011)0-(
)-1+|-2|
(2)(
)2÷
-
.
(1)
| 4 |
| 1 |
| 3 |
(2)(
| 2a |
| a-1 |
| a |
| a-1 |
| 4 |
| a-1 |
(1)原式=2+1-3+2
=2;
(2)原式=
×
-
=
-
=
=4.
=2;
(2)原式=
| 4a2 |
| (a-1)2 |
| a-1 |
| a |
| 4 |
| a-1 |
=
| 4a |
| a-1 |
| 4 |
| a-1 |
=
| 4a-4 |
| a-1 |
=4.
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