题目内容
因式分2(x-y)(x+y)-(x+y)2
2(x-y)(x+y)-(x+y)2,
=(x+y)[2(x-y)-(x+y)],
=(x+y)(x-3y).
=(x+y)[2(x-y)-(x+y)],
=(x+y)(x-3y).
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下列方程能用因式分解法解有( )
①x2=x ②x2-x+
=0 ③2x-x2-3=0 ④(3x+2)2=16
①x2=x ②x2-x+
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