题目内容
先化简再求值
÷(x+2-
),其中x=
-3.
| x-3 |
| x-2 |
| 5 |
| x-2 |
| 3 |
分析:先算括号里面的,再把除法变乘法,约分即可,最后把x的值代入计算.
解答:解:原式=
÷(
-
)
=
÷
=
×
=
,
当x=
-3时,原式=
=
=
.
| x-3 |
| x-2 |
| x2-4 |
| x-2 |
| 5 |
| x-2 |
=
| x-3 |
| x-2 |
| (x+3)(x-3) |
| x-2 |
=
| x-3 |
| x-2 |
| x-2 |
| (x+3)(x-3) |
=
| 1 |
| x+3 |
当x=
| 3 |
| 1 | ||
|
| 1 | ||
|
| ||
| 3 |
点评:本题考查了分式的化简求值,通分和约分是解此题的关键,此题是基础知识要熟练掌握.
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