题目内容
计算:
x2-(2x2-
xy+3y2)+
y2.
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分析:先去括号,再合并即可.
解答:解:原式=
x2-2x2+
xy-3y2+
y2=-
x2+
xy-
y2.
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点评:本题考查了整式的加减,解题的关键是去括号、合并同类项.
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