Question

化简 

4a2b3

x2-2x+1

÷

6ab

1-x2

•(ab)-2=______．

Answer 1

原式=

4a2b3

(x-1)2

×

-(x-1)(x+1)

6ab

×

1

a2b2

=

-2ab2(x+1)

3(x-1)

×

1

a2b2

=-

2(x+1)

3a(x-1)

．
故答案为：-

2(x+1)

3a(x-1)

．