题目内容
化简求值:2xy-
x2y3-
xy+
x2y3-
xy-1,其中x=-2,y=3.
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原式=(2xy-
xy-
xy)+(-
x2y3+
x2y3)-1
=-x2y3-1;
当x=-2,y=3时,原式=-(-2)2×33-1=-109.
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=-x2y3-1;
当x=-2,y=3时,原式=-(-2)2×33-1=-109.
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