题目内容
计算:(1)-15
| 1 |
| 3 |
| 1 |
| 7 |
| 2 |
| 3 |
| 1 |
| 7 |
(2)(8-1
| 1 |
| 3 |
| 4 |
| 3 |
(3)-32÷2
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 3 |
(4)2x2y-2xy-4xy2+xy+4x2y-3xy2
分析:(1)先根据去括号原则把括号去掉,然后都转化为分式,再化简求值.
(2)先把除化为乘,然后再去括号化简即可.
(3)先根据去括号原则把括号去掉,然后按加减乘除运算法则计算即可.
(4)合并同类项,化简即可.
(2)先把除化为乘,然后再去括号化简即可.
(3)先根据去括号原则把括号去掉,然后按加减乘除运算法则计算即可.
(4)合并同类项,化简即可.
解答:解:(1)原式=-
-
-
+
=-20+5
-15;
(2)原式=(8-
-0.4)×
=6-1-0.3
=4.7;
(3)原式=-9×
×
+4+
=-
+4+
=
;
(4)原式=6x2y-7xy2-xy;
| 46 |
| 3 |
| 14 |
| 3 |
| 22 |
| 7 |
| 57 |
| 7 |
=-20+5
-15;
(2)原式=(8-
| 4 |
| 3 |
| 3 |
| 4 |
=6-1-0.3
=4.7;
(3)原式=-9×
| 4 |
| 9 |
| 4 |
| 9 |
| 4 |
| 3 |
=-
| 16 |
| 9 |
| 4 |
| 3 |
=
| 32 |
| 9 |
(4)原式=6x2y-7xy2-xy;
点评:本题考查了整式的加减及有理数混合运算,是基础题.注意运算顺序.
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