题目内容
分解因式:
(1)x2y﹣2xy+y;
(2)3x3y﹣12xy.
(1)x2y﹣2xy+y;
(2)3x3y﹣12xy.
解:(1)x2y﹣2xy+y
=y(x2﹣2x+1)
=y(x﹣1)2;
(2)3x3y﹣12xy
=3xy(x2﹣4)
=3xy(x+2)(x﹣2).
=y(x2﹣2x+1)
=y(x﹣1)2;
(2)3x3y﹣12xy
=3xy(x2﹣4)
=3xy(x+2)(x﹣2).
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