题目内容
计算：（-2a-2）3b2÷2a-8b-3
原式=-8a-6b2÷2a-8b-3
=-8×
×b2÷（2×
×
）
=
÷
=
×
=-4a2b5．
=-8×
| 1 |
| a6 |
| 1 |
| a8 |
| 1 |
| b3 |
=
| -8 b2 |
| a6 |
| 2 |
| a8b3 |
=
| -8 b2 |
| a6 |
| a8b3 |
| 2 |
=-4a2b5．
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题目内容
| 1 |
| a6 |
| 1 |
| a8 |
| 1 |
| b3 |
| -8 b2 |
| a6 |
| 2 |
| a8b3 |
| -8 b2 |
| a6 |
| a8b3 |
| 2 |