题目内容
化下列各式为(x+m)2=n的形式.
(1)x2-2x-3=0______.
(2)x2+
x+1=0______.
(1)x2-2x-3=0______.
(2)x2+
| 2 |
(1)移项得x2-2x=3,
配方得x2-2x+1=3+1,
即(x-1)2=4;
(2)移项得x2+
x=-1,
配方得x2+
x+
=-1+
,
即(x+
)2=-
.
配方得x2-2x+1=3+1,
即(x-1)2=4;
(2)移项得x2+
| 2 |
配方得x2+
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
即(x+
| ||
| 2 |
| 1 |
| 2 |
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