题目内容
(1)分解因式:a3-ab2;
(2)计算:(
)-1+|1-
|-2cos45°.
(2)计算:(
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| 3 |
| 2 |
(1)a3-ab2=a(a2-b2)
=a(a+b)(a-b);
(2)(
)-1+|1-
|-COS45°
=3+
-1-2×
=2.
=a(a+b)(a-b);
(2)(
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| 3 |
| 2 |
=3+
| 2 |
| ||
| 2 |
=2.
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