题目内容
（1）计算：（-2-2+
）×6
-20080÷sin 45°；
（2）计算：
•(
)2-(
-
)．
| 1 |
| 3 |
| 8 |
（2）计算：
| m+1 |
| 2m2-2m |
| 2m |
| m+1 |
| 1 |
| m-1 |
| 1 |
| m+1 |
（1）原式=(-
+
)×12
-1÷
=
×12
-1×
=0；
（2）原式=
•
-
=
-
=
=
．
| 1 |
| 4 |
| 1 |
| 3 |
| 2 |
| ||
| 2 |
| 1 |
| 12 |
| 2 |
| 2 |
（2）原式=
| m+1 |
| 2m(m-1) |
| 4m2 |
| (m+1)2 |
| m+1-(m-1) |
| (m-1)(m+1) |
=
| 2m |
| (m-1)(m+1) |
| 2 |
| (m-1)(m+1) |
=
| 2(m-1) |
| (m-1)(m+1) |
| 2 |
| (m+1) |
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