题目内容
分解因式
(1)24x2y-28xy2
(2)(a2-2b)2-(1-2b)2.
(1)24x2y-28xy2
(2)(a2-2b)2-(1-2b)2.
(1)24x2y-28xy2=4xy(6x-7y);
(2)(a2-2b)2-(1-2b)2=(a2-2b+1-2b)(a2-2b-1+2b)=(a2-4b+1)(a2-1)=(a2-4b+1)(a+1)(a-1).
(2)(a2-2b)2-(1-2b)2=(a2-2b+1-2b)(a2-2b-1+2b)=(a2-4b+1)(a2-1)=(a2-4b+1)(a+1)(a-1).
练习册系列答案
相关题目