题目内容
计算:
(1)
×
+
×
-
;
(2)|
-2|-|1-
|-|
+
-5|;
(3)
×
-
;
(4)2
×
÷3
(a≥0,0<b<1).
(1)
| 3 |
| 2 |
| 4 |
| 1 |
| 2 |
| 144 |
| 3 | 1000 |
(2)|
| 3 |
| 2 |
| 2 |
| 3 |
(3)
| 27 |
| 3 |
| ||||
|
(4)2
| 1-b |
| ||
| 4 |
| b-b2 |
分析:(1)先把二次根式进行化简,再合并,即可求出答案;
(2)先把绝对值去掉,再去掉括号,然后合并,即可求出答案;
(3)先把二次根式进行化简,再根据二次根式的混合运算法则进行计算即可求出答案;
(4)先进行化简,再进行约分,即可求出答案;
(2)先把绝对值去掉,再去掉括号,然后合并,即可求出答案;
(3)先把二次根式进行化简,再根据二次根式的混合运算法则进行计算即可求出答案;
(4)先进行化简,再进行约分,即可求出答案;
解答:解:(1)
×
+
×
-
=
×2+
×12-10=3+6-10=-1;
(2)|
-2|-|1-
|-|
+
-5|=2-
-(
-1)-(5-
-
)=2-
-
+1-5+
+
=-2;
(3)
×
-
=3
×
-
=9-
=
;
(4)2
×
÷3
(a≥0,0<b<1)=2
×
÷3
=
÷3
=
.
| 3 |
| 2 |
| 4 |
| 1 |
| 2 |
| 144 |
| 3 | 1000 |
| 3 |
| 2 |
| 1 |
| 2 |
(2)|
| 3 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 2 |
| 3 |
(3)
| 27 |
| 3 |
| ||||
|
| 3 |
| 3 |
3
| ||||
|
5
| ||
| 3 |
27-5
| ||
| 3 |
(4)2
| 1-b |
| ||
| 4 |
| b-b2 |
| 1-b |
3ab
| ||
| 4 |
| b-b2 |
| ||||
| 2 |
| b-b2 |
| ab |
| 2 |
点评:此题考查了二次根式的混合运算;解题的关键要把二次根式化到最简,再进行计算,注意结果的符号.
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