题目内容
先化简,再求值:
÷(x-
),其中x=
+1.
| x-1 |
| x |
| 2x-1 |
| x |
| 3 |
原式=
÷
=
•
=
,
当x=
+1时,原式=
=
=
.
| x-1 |
| x |
| x2-2x+1 |
| x |
=
| x-1 |
| x |
| x |
| (x-1)2 |
=
| 1 |
| x-1 |
当x=
| 3 |
| 1 | ||
|
| 1 | ||
|
| ||
| 3 |
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题目内容
| x-1 |
| x |
| 2x-1 |
| x |
| 3 |
| x-1 |
| x |
| x2-2x+1 |
| x |
| x-1 |
| x |
| x |
| (x-1)2 |
| 1 |
| x-1 |
| 3 |
| 1 | ||
|
| 1 | ||
|
| ||
| 3 |