题目内容
先化简,再求值:7a2b+(-4a2b+5ab2)-(2a2b-3ab2),其中a=2、b=3.
7a2b+(-4a2b+5ab2)-(2a2b-3ab2)
=7a2b-4a2b+5ab2-2a2b+3ab2
=7a2b-4a2b-2a2b+5ab2+3ab2
=a2b+8ab2,
将a=2,b=3代入原式得:
原式=22×3+8×2×32
=12+144
=156.
=7a2b-4a2b+5ab2-2a2b+3ab2
=7a2b-4a2b-2a2b+5ab2+3ab2
=a2b+8ab2,
将a=2,b=3代入原式得:
原式=22×3+8×2×32
=12+144
=156.
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