题目内容
已知a=| 1 | ||
2+
|
| 1-2a+a2 |
| a-1 |
| ||
| a2-a |
分析:先化简,再代入求值即可.
解答:解:∵a=
,
∴a=2-
<1,
∴原式=
-
=a-1-
=a-1+
=2-
-1+2+
=4-1
=3.
| 1 | ||
2+
|
∴a=2-
| 3 |
∴原式=
| (a-1)2 |
| a-1 |
| ||
| a(a-1) |
=a-1-
| 1-a |
| a(a-1) |
=a-1+
| 1 |
| a |
=2-
| 3 |
| 3 |
=4-1
=3.
点评:本题考查了二次根式的化简与求值,将二次根式的化简是解此题的关键.
练习册系列答案
相关题目