题目内容
先化简,后求值:(x-y)2+(2x+y)(2x-y)-2(2x2+xy),其中x=-1,y=
.
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(x-y)2+(2x+y)(2x-y)-2(2x2+xy)
=x2-2xy+y2+4x2-y2-(4x2+2xy)
=x2-2xy+y2+4x2-y2-4x2-2xy
=x2-4xy,
当x=-1,y=
时,原式=(-1)2-4×(-1)×
=1+1=2.
=x2-2xy+y2+4x2-y2-(4x2+2xy)
=x2-2xy+y2+4x2-y2-4x2-2xy
=x2-4xy,
当x=-1,y=
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