题目内容
计算:(1)
| 2 |
| ||
| 4 |
(2)
| 2 |
| (-3)2 |
分析:分别把30°、45°、60°角的三角函数值代入原式计算即可.
解答:解:(1)
(2cos45°-sin60°)+
,
=
(2×
-
)+
,
=2-
+
,
=2.
(2)
sin45°+cos30°•tan60°-
,
=
×
+
×
-3
=1+
-3,
=-
.
| 2 |
| ||
| 4 |
=
| 2 |
| ||
| 2 |
| ||
| 2 |
| ||
| 4 |
=2-
| ||
| 2 |
| ||
| 2 |
=2.
(2)
| 2 |
| (-3)2 |
=
| 2 |
| ||
| 2 |
| ||
| 2 |
| 3 |
=1+
| 3 |
| 2 |
=-
| 1 |
| 2 |
点评:解答此题要熟悉三角函数的特殊值以及有理数的混合运算法则,难度不大.
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