题目内容
先化简,再求值:
+
÷
,其中x=4.
| x-4 |
| x-2 |
| 4 |
| x2-4x+4 |
| x |
| x-2 |
分析:先计算除法,再计算加法,最后把x的值代入计算即可.
解答:解:原式=
+
×
=
+
=
=
,
当x=4时,原式=
=
.
| x-4 |
| x-2 |
| 4 |
| (x-2)2 |
| x-2 |
| x |
| x-4 |
| x-2 |
| 4 |
| x(x-2) |
| (x-2)2 |
| x(x-2) |
| x-2 |
| x |
当x=4时,原式=
| 4-2 |
| 4 |
| 1 |
| 2 |
点评:本题考查了分式的化简求值,解题的关键是注意通分、约分,以及分子分母的因式分解.
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