题目内容
先化简,再求值(1-
)÷
,其中x=2sin45°+1.
| x |
| x+1 |
| x2-1 |
| x2+2x+1 |
(1-
)÷
=
•
=
,
当x=2sin45°+1=2×
+1=
+1时,
原式=
=
.
| x |
| x+1 |
| x2-1 |
| x2+2x+1 |
=
| 1 |
| x+1 |
| (x+1)2 |
| (x+1)(x-1) |
=
| 1 |
| x+1 |
当x=2sin45°+1=2×
| ||
| 2 |
| 2 |
原式=
| 1 |
| x+1 |
| ||
| 2 |
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