题目内容
已知
=
，求
的值．
| x |
| x2-1+1 |
| 1 |
| 3 |
| x2 |
| x2+x+1 |
∵
=
=
，
∴x=3，
则原式=
=
．
| x |
| x2-1+1 |
| 1 |
| x |
| 1 |
| 3 |
∴x=3，
则原式=
| 9 |
| 9+3+1 |
| 9 |
| 13 |
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题目内容
| x |
| x2-1+1 |
| 1 |
| 3 |
| x2 |
| x2+x+1 |
| x |
| x2-1+1 |
| 1 |
| x |
| 1 |
| 3 |
| 9 |
| 9+3+1 |
| 9 |
| 13 |