题目内容
计算
(1)﹣3﹣4+19﹣(+11)﹣(﹣2)
(2)﹣3÷(﹣5)×
(3)(
﹣
﹣
)×(﹣60)
(4)(﹣1)100﹣
×[3﹣(﹣3)2].
(1)﹣3﹣4+19﹣(+11)﹣(﹣2)
(2)﹣3÷(﹣5)×
(3)(
(4)(﹣1)100﹣
解:(1)原式=﹣3﹣4+19﹣11+2
=﹣18+21
=3;
(2)原式=3×
×
=
;
(3)原式=﹣
×60+
×60+
×60
=﹣40+5+4
=﹣31;
(4)原式=1﹣
×(3﹣9)
=1+1
=2.
=﹣18+21
=3;
(2)原式=3×
=
(3)原式=﹣
=﹣40+5+4
=﹣31;
(4)原式=1﹣
=1+1
=2.
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