题目内容
(1)化简:7ab+(-8ac)-(-5ab)+10ac-12ab
(2)计算:0.25×(-2)3-[4÷(-
)2+1]+(-1)2005
(2)计算:0.25×(-2)3-[4÷(-
| 2 |
| 3 |
(1)原式=7ab-8ac+5ab+10ac-12ab
=(5+7-12)ab+(-8+10)ac
=2ac;
(2)原式=
×(-8)-[4×
+1]+(-1)
=(5+7-12)ab+(-8+10)ac
=2ac;
(2)原式=
| 1 |
| 4 |
| 9 |
| 4 |
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